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αAπΣ∞∂θ√x²≠∫÷≤%+−½αβΔλφ³≈∑°
  1. Home/
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  3. Grade 8/
  4. Unit 5/
  5. Systems by Graphing
Grade 8 · Unit 5Topic 1 of 2~22 min

Systems by Graphing

The solution is the point where the two lines cross.

All topics in this unit
αAπΣ∞∂θ√x²≠∫÷≤%+½αβΔ
Step 1 · Learn

Walkthrough

Read this first — it covers the idea in plain language with a worked example.

Graph both lines

  1. 1Write each equation in slope-intercept form if needed.
  2. 2Graph both lines on the same grid.
  3. 3The intersection point is the solution.
Worked example

Where do y = x + 1 and y = -x + 3 intersect?

  1. →Graph both lines.
  2. →They cross at (1, 2).
  3. →Check: 1 + 1 = 2 ✓ and -1 + 3 = 2 ✓.

Special cases

Parallel lines never cross → no solution. Identical lines overlap everywhere → infinitely many solutions.

αAπΣ∞∂θ√x²≠∫÷≤%+½αβΔ
Step 2 · Watch

Video walkthrough

A short video that walks through this topic.

Other

Solving a System by Graphing

Graph both lines and read the intersection point.

Watch on YouTube
αAπΣ∞∂θ√x²≠∫÷≤%+½αβΔ
Step 3 · Practice

Practice

Try a worksheet or work through some problems before the quiz.

Khan Academy

Systems by graphing

Open resource
πΣ√≠≤+αβΔπΣx²θ÷+
Step 4 · Check

Quick check

A couple of questions to make sure this topic stuck. Retake as many times as you want.

Systems by Graphing

Question 1 of 2

Easy

The solution to a system of two lines is found where the lines do what?

αAπΣ∞∂θ√x²≠∫÷≤%+½αβΔ
←Back toUnit 5 overview→Next up · Topic 2 of 2Solving Systems Algebraically